A COPPER WIRE OF LENGTH 4M AND AREA OF CROSS-SECTION 1.2CM^2 IS STRECHED WITH A FORCE 4.8×10^3 N . IF YOUNGS MODULAS FOR COPPER IS 1.2×10^11 N/M WHAT IS THE INCREMENT OF LENGTH OF THE WIRE .. NEED THE ANSWER SOON MAYBE IN SOME MINUTES

HOPE YOU WILL ANSWER

Stress = force / area

= 4.8 x 10³ / 1.2 x 10^-4

= 4 x 10⁷ N /m²

YOUNGS MODULAS = stress / strain

= 4 x 10⁷ / 1.2 x 10^11

= 3.3 x 10^-4

INCREMENT OF LENGTH = longitudinal length x intitial length

= ( 3.3 x 10^-4 ) x 4

= 13.2 x 10^-4 m

= 13.2 mm

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15.3 cos 65 degrees trig

it is called kinetic energy