A baseball is thrown at an angle of 22◦ relative to the ground at a speed of 24.5 m/s. The ball is caught 42.5045 m from the thrower. The acceleration due to gravity is 9.81 m/s. How high is the tallest spot in the ball’s path? Answer in units of m.

i would think it's food chain

the rearrangement of particles in a physical change. hope this

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

the right answer is 0.3 meters per second