work of 4 joules is done in stretching a spring from its natural length to 11 cm beyond its natural length. what is the force (in newtons) that holds the spring stretched at the same distance (11 cm)

Which statement best explains why an object weight less on mercury than it does on earth

What is the most useful equation for electric power?

Ahanging spring stretches by 35.0 cm when an object of mass 450 g is hung on it at rest. in this situation, we define its position as x = 0. the object is pulled down an additional 18.0 cm and released from rest to oscillate without friction. what is its position x at a moment 84.4 s later? express your answer in cm.