A marble with a mass of 1. 5 grams rolls at a constant rate of 0. 50 cm/s across a table. What is the magnitude of the marble's momentum?.

Explanation:

The momentum can be calculated as follows:

p = mv

Where m is the mass of the marble and v its velocity. Therefore:

p = 0.0015kg · 0.0005m/s = 0.0000075 kg·m/s = 7,5·10^{-6}kg·m/s

Note that we have converted the grams in kg and cm/s in m/s.

7.5 × 10⁻⁶ kgm/s.

Explanation:

Data:

Mass = 1.5 g => 0.0015 kg

Velocity = 0.5 cm/s => 0.005 m/s

Momentum = ?

Formula:

Momentum = Mass × Velocity

P =mv

Solution:

Momentum = 0.0015 kg × 0.005 m/s

Momentum = 0.0000075 kgm/s => 7.5 × 10⁻⁶ kgm/s

The magnitude of the marble's Momentum is 7.5 × 10⁻⁶ kgm/s.

c. rb

explanation:

the atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons.

the answer is a 3.8cm

explanation: