Particles q1, 92, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 0,92 = +2.50 x 10-6 C,
and q3 = -2.50 x 10-6 C. Particles q1 and q2 are
separated by 0.500 m. Particles q2 and q3 are
separated by 0.250 m. What is the net force on 92?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
-5.00 x 10-60
-2.50 x 10-6C
+2.50 x 10-6 C
+92
91
93
0.500 m
0.250 m

Ibelieve the answer you're looking for is

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.

There are no answer choices, but a metaphor is a comparison between two objects that are not usually related without using like or as.