Two blocks are accelerated across a horizontal frictionless surface as shown. Frictional forces keep the two blocks from sliding relative to each other, and the
two move with the same acceleration. If F = 1.2 N and M-1.0 kg, what is the horizontal component (frictional force ) of the force of the small block on the large block?

0.48 N to the right
b. 0.72 N to the right
c. 0.72 N to the left
d. 0.48 N to the left
e. 0.65 N to the left

The answer is  a.first and third quarters 

You need to be more specific.  i really don't know what a "motion map" is.you can draw a graph of an object's position, distance, displacement, speed,velocity, or acceleration versus time, or you can draw a graph of the object's x-position versus its y-position and not give any information about time at all.if the graph presents position or displacement against time,  then constant velocity is a straight line . . i.e. a line that has  constant slope.if the graph shows speed against time, then constant velocityis a horizontal piece of line.if the graph shows acceleration against time, then constant  velocity is a piece of line that lies on the x-axis . . it's value is zero. 

'b ' is the correct conclusion.

The answer would be d. hope this :