HELP A .01 Kg dort gets thrown at Max's (110 Kg) shoulder at a velocity of 30m/s. It becomes lodged in Max's shoulder and the dart+Max mass travels at a rate of 0.1 m/s in the same direction as the dart's original path

What is the change in Kinetic Energy before and after the dart pierced his shoulder?

The kinetic energy before it hits Max’s shoulder is

1/2 mv^2

Where m is mass
v is velocity

So, the kinetic energy of the dart before it’s hits the poor kid is

Ek = 1/2 • 0.1 • 30^2

Ek = 45J

Then, we see that the dart comes to a stop inside Max’s shoulder. This means there’s no movement, and therefore no kinetic energy.

Change is always (final - initial)

So, (0-45) = -45 Joules.

Mark brainliest!

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