Given the arrangement of charged particles shown in the figure below, find the net electrostatic force on the Q2 = 2.00−nC charged particle located at the origin. (Express your answer in vector form. Assume Q1 = −16.00 nC and Q3 = 5.00 nC.) F = ? N

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

the ima (higher than 1m) will be greater than the ima with the height of 1m.