A charge Q1 = 24C is at rest and is located 3 cm away from another fixed charge Q2 = 6 u C. The first charge is then released. Calculate the kinetic energy of charge Q1 when it is 7 cm away
from charge q2

i need the answer to this too but idk it ; -;

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation