1, A car is moving over a straight path covers a distance x with constant speed of 10m/s and then the same distance with constant speed of V2.If average speed of the car is 16m/s then V2=? 2, A car covers one third part of its straight path with speed V1 and the rest with speed V2. what is its average speed?
3, A bus travels between two points A and B. V1 and V2 are its average speed and average velocitythe
A, V1>V2 B, V1<V2 C, V1=V2 D, V1><V2

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y