PLEASE HELP ASAP WILL REWARD BRAINLIEST:)) A cell of e. m.f. 2.0 V can drive a current of 0.5 A round a circuit for 10 hours. How much chemical energy is transferred to electrical energy in this time? How long would you expect the same cell to maintain a current of 0.2 A?

Explanation:

Let's assume the circuit runs DC with a purely resistive load, and every component has efficiency 1, so no energy is dissipated.

The power generated by the cell is equal to the power absorbed by the load, which is the product of the tension drop (equal to the emf generated by the cell by KVL) times the current flowing through it: . Remembering the definition of power and the relationship with energy, we obtain

If the current becomes , and the energy stored inside the cell doesn't change, you just scale up by a factor , thus taking 25 hours to discharge. How?

The power absorbed with the new, smaller current, is . Back to the definition of power, replacing this new value and keeping the same energy value in the cell we get

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2