A vessel with vertical sides and a base area of 0.0050 m² contains mercury of density 13 600 kg/m³ and depth 0.60 m³ (Take the weight of 1 kg to be 10 N.) Calculate (a) the weight of mercury in the vessel. (b) the pressure that the mercury exerts on the base of the tank.

volume of vessel =Base area×H

=0.050×6m³

=0.30m³

density of mercury

13600kg/m³

mass of mercury in 1m³ =13600kg

mass of mercury in 0.30m³vessel =136000×0.30

=40800kg

pressure of mercury on vessel

=pgh

=40800*10*6. (where p=amount of mercury. g=acceleration due to gravity. h=height of the vessel)

=2448000kg.m/s²

Sure hope this helps and pls mark me BRAINIEST

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.