A student eats a dinner contaning 8.0×10⁶J of energy. He wishes to do an equivalent amount of work in a near by gym by lifting a 60 kg object to expand this much energy? Assume that he raises it a distance of 2.0m each time.

6802 times

Explanation:

W = F x S

8 x 10⁶ = n x 60 x 9.8 x 2

n = 8 x 10⁶ / 1176

n = 6802 (approx.)

answer: option c.

explanation:

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west