Starting from rest, a car accelerates at 2.4 m/s2 up a hill that is inclined 5.5â° above the horizontal. how far horizontally and vertically has the car traveled in 12 s?

The car travels 172.0m horizontally and 16.6m vertically The car travels 172.8m in 12s, given by the equation d = ½at² = ½ * 2.4m/s² * (12s)² The horizontal distance is given by x = d * cos(θ) = 172.8m * cos(5.5°) = 172.0m The vertical distance is given by y = d * sin(θ) = 172.8m * sin(5.5°) = 16.6m NOTE: when calculating cos() and sin(), make sure your calculator is in degree mode

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