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Physics, 02.07.2019 06:40 neyssa83

Aspring whose natural length is 1010 cm exerts a force of 3030 n when stretched to a length of 1515 cm. (note 1515 cm - 1010 cm = 55 cm = .05.05 m ) find the spring constant k=k= 2 determine the work done in stretching the spring 77 cm ( =.07=.07 m) beyond its natural length. w=w= joules

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