Afarm tractor tows a 4080 kg trailer up a 14.5° incline at a steady speed of 3.0 m/s. what force does the tractor exert on the trailer? (ignore friction.)

Force due to gravity = 4080 x 9.81 = 40,025 N 
Force of trailer parallel to slope = 40025 sin 14.5 = 10021 N (resolve horizontally) 
I used the acceleration of gravity as 9.81 m/s. If they want you to use 10 m/s, just switch it with the 9.81 in the first equation. Ignore the speed of the trailer. That is just to throw you off.

Question was not very clear if there are specific answer choices tell me and i'll try to you more. hope this though2 laps is 1 min. we know that for each min she does two times the amount of laps. for 12 laps we can do 12/2 which does give us 12 laps in 6 mins not 16 mins.