Abox of mass 5.0 kg is accelerated from rest by a force across a floor at a rate of 2.0 m/s2 for 7.0 s. find the net work done on the box.

The net work done on the box weighing 5.0 kg and accelerated from rest by a force across a floor is 490 Nm.

Given the following data:

To find the net work done on the box:

First of all, we would determine the force acting on the box:

×

×

Force = 10 Newton

Next, we would use the second equation of motion to determine the distance traveled by the box:

Where:

Substituting the given parameters into the formula, we have;

Distance, S = 49 meters.

Now, we can determine the net work done on the box:

×

×

Work done = 490 Nm

Therefore, the net work done on the box is 490 Nm.

Work done on the box is 490 joules.

Explanation:

It is given that,

Mass of the box, m = 5 kg

Initial speed of the box, u = 0

Acceleration of the box,

Time taken, t = 7 s

The force is calculate using the product of mass and acceleration. It is given by :

F = ma

Let d is the distance covered by the box. Using the equation of motion as :

d = 49 m

The product of force and distance is equal to the work done on the box. It is given by :

W = 490 joules

So, the work done on the box is 490 Joules. Hence, this is the required solution.

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