An 880n box is pushed across a level floor for a distance of 5.0m with a force of 440n. how much work was done on the box

The work done on the box is 2200 J.

To calculate the work done on the box, we use the formula below.

Formula:

Where:

From the question,

Given:

Hence, The work done on the box is 2200 J.
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W = 2,200 joules

Explanation: Work is defined as a motion caused by a force, and can be calculated as:

W = F*d

where F is the force applied and d is the distance moved, here F = 440n and d = 5.0m

(the mass of the box does not matter in this case, where there are no friction and the movement is only in the perpendicular axis with respect at the direction in wich the weight pushes)

So the total work is:

w = 5.0m*440N = 2,200j

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .