At the moment car a is starting from rest and accelerating at 5.0 m/s2, car b passes it moving at a constant speed of 45m/s. how long will it take car a to catch up with car b?

X=v(initial)t+.5(a)t^2. Car B's displacement can be represented by equation x=45t. Car A can be represented by the equation x=.5(5)t^2. Plug these equations into a graphing calc and find intercept, the x value is time, the y is displacement. 

I'd go for the one that says that knees are fulcrums, lower legs are levers and the ankles hold loads.hope it ,happy homework/ study/ exam!