Physics, 24.08.2019 07:30 Rodrigo6379

Acar traveling with constant speed travels 150 km in 7200 s. what is the speed of the car?
express the speed to two significant figures and include the appropriate units.

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Answer from: lillitzy8865

The speed of the car is 75 km/h

Further explanation

These are the formulas that we have to remember before solving the problem.

Speed is the rate of change of distance.

$\large { \boxed {v = \frac{d}{t}}}$

v = speed ( m/s )

d = distance ( m )

t = time ( s )

Acceleration is the rate of change of velocity.

$\large { \boxed {a = \frac{\Delta v}{t}}}$

a = acceleration ( m/s² )

Δv = change in speed ( m/s )

t = time ( s )

Let us now tackle the problem!

Given:

distance = d = 150 km

time taken = t = 7200 s = 2 hours

Unknown:

velocity = v = ?

Solution:

$v = \frac{d}{t}$

$v = \frac{150}{2}$

$\large {\boxed {v = 75~km/h} }$

The acceleration of the car is 0 m/s² because it travels with constant speed.

We could also plot the distance vs time graph as shown in the attachment.

Learn moreVelocity of A Runner : linkKinetic Energy : linkAcceleration : linkAnswer details

Grade: Middle School

Subject: Physics

Chapter: Kinematics

Keywords: indycar top speed of a fastest police car has ever gone

Acar traveling with constant speed travels 150 km in 7200 s. what is the speed of the car? express

Answer from: niyahdabadest

The speed of the car to 2 significant figures is $\boxed{21\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}}$ .

Further Explanation:

Given:

The distance covered by the car is $150\,{\text{km}}$ .

The time taken by the car to cover the distance is $7200\,{\text{s}}$ .

Concept:

The speed of a car defined as the ratio of the distance and the time taken by the car in covering that distance.

Write the expression for the speed of the car as:

$v = \dfrac{{{\text{distance}}}}{{{\text{time}}}}$ …… (1)

Here, is the speed of the car.

The distance covered by the car in meters is.

$\begin{aligned}d&= 150 \times {\text{1000}}\,{\text{m}}\\{\text{ 1}}&={\text{.50}} \times {\text{1}}{{\text{0}}^5}\,{\text{m}}\\\end{aligned}$

Substitute the values in the above expression.

$\begin{aligned}v&= \frac{{1.50 \times {{10}^5}\,{\text{m}}}}{{7200\,{\text{s}}}}\\&= \frac{{1500}}{{72}}\,{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}\\&= 20.83\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}\\&\approx 21\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}\\\end{aligned}$

Thus, the speed of the car to 2 significant figures is $\boxed{21\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}}$ .

Learn More:

A test car travels in a straight line along the x axis, the graph in the figure shows link If no friction acts on a diver during a dive, then which of the following statements is true link A 1500-kg car accelerates from rest to 25 m/s in 7.0 s. What is the average power delivered by the link

Answer Details:

Grade: Middle School

Chapter: Speed and distance

Subject: Physics

Keywords: Speed, velocity, distance, time, distance of 150 km, in 7200 s, speed of the car, ratio of distance, rate of change of distance, 20.83 m/s, 21m/s.

Answer from: Quest

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.

Answer from: Quest

weight of the box is given as

$w = 112.1 n$

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

$w_x = w sin\theta$

here we have

$w = 112.1 n$

$w_x = 112.1 sin42$

$w_x = 75 n$

so it requires 75 n force to move it upwards

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Acar traveling with constant speed travels 150 km in 7200 s. what is the speed of the car?
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