The height, s, of a ball thrown straight down with initial speed 64 ft/sec from a cliff 80 feet high is s(t) = â16t2 â 64t + 80, where t is the time elapsed that the ball is in the air. what is the instantaneous velocity of the ball when it hits the ground?

The height of the ball (ft), measured upward from the ground is
s(t) = 16t² + 64t + 80
where t = time when the ball is in the air.

When the ball hits the ground, s = 0. The time(s) when this occurs is given by
16t² + 64t + 80 = 0
Divide through by 16.
t² + 4t + 5 = 0
(t - 1)(t + 5) = 0
t = 1 or t = -5 s
Reject negative time, so that
t = 1 s

The velocity function is
v(t) = 64 + 32t
When t = 1 s, obtain
v(1) = 96 ft/s

The ball hits the ground with velocity 96 ft/s.

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stands for electromotive force and it is measured in volts. despite its name, it is not actually the force in the sense of being a "pushing" or "pulling" (not measured in newtons).an equation that relates emf,  ℰ,  to a battery's terminal voltage, v, current, i, and internal resistance, r, is    ℰ = v + irin this case, the emf can be interpreted as a voltage—a difference in electric potential.i would not say that it would be considered an energy. if emf can be defined as the energy/work per a unit charge from a battery or other electric source, then it is not strictly energy.