Without the wheels, a bicycle frame has a mass of 8.47 kg. each of the wheels can be roughly modeled as a uniform solid disk with a mass of 0.820 kg and a radius of 0.343 m. find the kinetic energy of the whole bicycle when it is moving forward at 3.55 m/s.

Refer to the diagram shown below.

Given:
m₁ = 8.47 kg, the mass of the bicycle frame
m₂ = 0.82 kg. the mass of each wheel
r = 0.343 m, the radius of each wheel
v = 3.55 m/s, forward velocity.

The moment of inertia of each wheel is
I = (1/2)*m₂*r² = 0.5*(0.82 kg)*(0.343 m)² = 0.048224 kg-m²

The angular velocity of each wheel is
ω = (3.55 m/s)/(0.343 m) = 10.35 rad/s

The kinetic energy of the bicycle is
KE = (1/2)*m₁*v² + 2*(1/2)*I*ω²)
     = 0.5*(8.47 kg)*(3.55 m/s)² + (0.048224 kg-m²)*(10.35 rad/s)²
     = 58.5375 J

58.54 J

The charge of an ion with 55 protons and 52 electrons is +3. the reason is because protons are positive, and there are three more than the amount of negative electrons.