A1423 kg car is traveling down the road at 105.0 km/h. while traveling at this rate of speed, what is the kinetic energy of this vehicle in kilojoules?

605.3 kilojoules First, convert the 105.0 km/h to m/s 105.0 km/h * 1000 m/km / 3600 s/h = 29.16666667 m/s Now calculate the energy using the E = 0.5 M V^2 formula E = 0.5 * 1423 kg * (29.16666667 m/s)^2 E = 711.5 kg * 850.69 m^2/s^2 E = 605269.0972 (kg m^2)/s^2 E = 605269.0972 J E = 605.2690972 kJ Rounding to 4 significant figures gives 605.3 kilojoules

Is a  vector quantity  that refers to "the rate at which an object changes its position." imagine a person moving rapidly - one step forward and one step back - always returning to the original starting position. while this might result in a frenzy of activity, it would result in a zero velocity. because the person always returns to the original position, the motion would never result in a change in position. since velocity is defined as the rate at which the position changes, this motion results in zero velocity. if a person in motion wishes to maximize their velocity, then that person must make every effort to maximize the amount that they are displaced from their original position. every step must go into moving that person further from where he or she started. for certain, the person should never change directions and begin to return to the starting position.