Ingrid kicks a football with an initial velocity of 12 m/s at an angle of 45 degrees relative to the ground. the horizontal component of the initial velocity to the nearest tenth is?

8.5m/s

Explanation:

Given the initial velocity to be 12m/s at an angle of 45° to the ground. The horizontal component of the velocity can be expressed as U cos (theta) where;

U is the initial velocity of the object

theta is the angle between the initial velocity and the horizontal. Mathematically, Ux = Ucos(theta)

Ux = 12cos45°

Ux = 12×1/√2

Ux = 12×√2/2

Ux = 6√2m/s

Ux = 8.48m/s

Ux = 8.5m/s(to nearest tenth)

okay i have so many questions. but the big one here is: um wt..f is this mess? ?