An 8.0 cm object is 40.0 cm from a concave mirror that has a focal length of 10.0 cm. its image is 16.0 cm in front of the mirror. the height of the image produced by the mirror, to the nearest tenth, is cm.

3.2 cm

Explanation:

The magnification of a concave mirror is given by:

where, h' is the height of the image, h is the height of the object, v is the image distance and u is the object distance.

Given:

h = 8.0 cm

u= - 40.0 cm

v= - 16.0 cm

Height of the image = 3.2 cm

Diminished, real and inverted image would be formed.

h' = -3.2 cm                                

Explanation:

It is given that,

Size of the object, h = 8 cm

Object distance, u = -40 cm

Focal length of the mirror, f = -10 cm

Image distance, v = -16 cm

Let h' is the height of the image produced by the mirror. Using the formula of magnification of mirror as :

h' = -3.2 cm

So, the height of the image produced by the mirror is 3.2 cm. Hence, this is the required solution.

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)

blue light is scattered in different directions by the tiny molecules of air. blue is scattered more than other colours because it has a shorter distance to travel which results in smaller waves. this is why we see a blue sky most of the time.