Aheat engine operating between energy reservoirs at 20∘c and 600∘c has 30% of the maximum possible efficiency. part a how much energy must this engine extract from the hot reservoir to do 1000 j of work

5020 Joules. The maximum theoretical efficiency of an heat engine is e = 1 - Tc/Th where e = efficiency Tc = cold temperature (absolute) Th = hot temperature (absolute) So let's convert the temperatures from C to K. Tc = 20 + 273.15 = 293.15 K Th = 600 + 273.15 = 873.15 K And substitute the values into the formula. e = 1 - 293.15/873.15 e = 1 - 0.335738418 e = 0.664261582 Since our engine is only operating at 30% of this efficiency, the actual efficiency is 0.3 * 0.664261582 = 0.199278474 So in order to do 1000 J of work, 1000 J / 0.199278474 = 5018.103448 J of energy must be extracted from the hot reservoir. Rounding to 3 significant figures gives 5020 Joules.

Aform of energy that is reflected or emitted from objects in the form of electrical and magnetic waves that can travel through space. there are many forms of  electromagnetic  energy including gamma rays, x rays, ultraviolet radiation, visible light, infrared radiation, microwaves and radio waves.

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