Can someone explain the steps for this ? a lovesick lad wants to throw a bag of candy and love notes into the open window of his girlfriend's bedroom above. assuming it just reaches the window, he throws the love gifts at 16.2 m/s and 60 degrees to the ground. how high up is the window?

h = 10.0 m

Explanation:

As we know that the initial velocity of the bag is 16.2 m/s at an angle of 60 degree

so here we have

now we know that the bag just reaches the window so here at the point when bag reaches to the window its vertical speed must be zero

so we have

trig 15.3 cos

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west