Two stretched cables both experience the same stress. the first cable has a radius of 3.3x10-3 m, and is subject to a stretching force of 290 n. the radius of the second cable is 5.5x10-3 m. determine the stretching force on the second cable.

Stress is the force per unit area or pressure. Let's find the stress for the first cable.

S = F/A = 290 N/ [π*(3.3×10⁻³ m)²] = 8476571.808 Pa

We equate this to that of the second cable.

8476571.808 Pa = F/[π*(5.5×10⁻³ m)²]
Solving for F,
F = 805.56 N

Alkaline earth metals are found in group 2 of the periodic table.