Aplatinum sphere with radius 1.65 cm is totally immersed in mercury. find the weight of the sphere, the buoyant force acting on the sphere, and the sphere\'s apparent weight. the densities of platinum and mercury are 2.14 × 104 kg/m3 and 1.36 × 104 kg/m3, respectively.

Gvn that, Radius r = 1.65cm then the Diameter d = 3.3 cm Volume V = 4/3pi*(D/3)^3 = 4/3*3.14*(3.3)^3/8 = 4/3*3.14*35.937/8 = 4/3*3.14*4.492125 = 4/3*14.1052725 = 56.421.9/3 = 18.80703 dm^3 We know that gravity g=9.806m/s^2 p pt = 2.14 * 104 kg/m^3 = 21.4 p hg = 1.36 * 104 kg/m^3 = 13.6 Real Weight Wr = V*p pt*g = 18.80703*21.4*9.806 = 3946.625 N Buoyant force Fb= V*p hg*g = 18.80703*13.6*9.806 = 2508.136 N Apparent weight = Wr-Fb = 3946.625-2508.136 = 1438.489 N Therefore Apparent weight is 1438.489 N

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