Mastering physics two particles are separated by a certain distance. the force of gravitational interaction between them is f0. now the separation between the particles is tripled. find the new force of gravitational interaction f1.

f1 = f0/9 The gravitational force between two points is described as F = G*m1*m2/r^2 where F = Force G = Gravitational constant m1, m2 = masses r = distance between centers of masses Since everything is remaining constant except r, we can ignore their actual values and simply compare the value of 1/r^2 and 1/(3r)^2. So let's do so: 1/(3r)^2 / 1/r^2 = 1/(3r)^2 * r^2/1 = r^2/(3r)^2 = r^2/(9r^2) = 1/9 So the value of f1 will be one ninth of the value of f0, giving f1 = f0/9

Answer: buoyancy forceexplanation: in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.