The mass of the sun is 2 × 1030 kg, and the mass of saturn is 5.68 × 1026 kg. the distance between saturn and the sun is 9.58 au. veronica is solving the following equation to calculate the orbital period of saturn, but there is an error in the equation. t = what should veronica change to correct the equation? a. change the position of 2 x 1030 kg and 9.58 au b. change 2 x 1030 kg to 5.68 x 1026 kg c. change the square root to a cube root d. change 9.58 au to the distance in meters

The formula for calculating the orbital time period of a body is given as:
T² = 4π²r³ / GM
Where T is the time periodr is the distance between the two bodiesG is the gravitational constant andM is the mass of the body that is being orbited.
If we compute this time using SI units, the working is:9.58 AU is 1.43 x 10¹² meters
T = √[(4*π²*(1.43 x 10¹²)³) / (6.67 × 10⁻¹¹ * 2 x 10³⁰)]T = 9.30 x 10⁸ seconds which is approximately 29 years

By means of the astronomical units, distance is in astronomical units and the mass is in solar masses. In these conditions, the ratio:4π²/G = 1 so
T² = a³ (when the solar mass of the sun is 1)
T = √(9.58)³T = 27 years

The horse latitudes-high-pressure zones about 30 degrees north and 30 degrees south of the equator.-warm air traveling away from the equator cools and sinks-weather tends to be clear and drythe doldrums-low-pressure near equator-air rises and spreads out toward the poles-rising moist air produces clouds and heavy rainthe westerlies-blow from the west-move from the horse latitudes toward the poles.-bring storms across much of the united statesthe tradewinds-blow from the east-move from the horse latitudes toward the equator  -strong, steady winds