Aphonograph record 30.0cm in diameter rotates 33.5 times per minute. what is its frequency? what is its period? what is the linear speed of a point on its rim? what is the centripetal acceleration of a point on its rim?

Explanation:

Given that phonograph rotates 33.5 times per minute:

Frequency of the phonograph =

Time period =

time period = 0.0298 × 60 seconds =1.788 seconds

Radius r = 15 cm = 0.15 m (1 m = 100 cm)

The linear speed =

The centripetal acceleration of a point on its rim:

Centripetal acceleration is .

12000j is work done

d) physical means can be used to separate the components of air.