The mass of the earth is 5.98 x 1024 kg and the radius of the earth is 6370km. use this to find the acceleration due to gravity near the surface of the earth. (find f and then use f/m to find the acceleration) m/s2

G=(G*M)/r²
g-acceleration due the gravity, g=?
G-the universal gravitational constant, G=6.673x10^(-11)N*m²/kg²
M-the mass of the earth, M=5.98x10^(24)kg
r-the radius of the earth, r=6370km=6370000m
g=(6.673x10^(-11)N*m²/kg²)*(5.98x10^(24)kg)/(6370000m)²
g=9.834m/s²

stands for electromotive force and it is measured in volts. despite its name, it is not actually the force in the sense of being a "pushing" or "pulling" (not measured in newtons).an equation that relates emf,  ℰ,  to a battery's terminal voltage, v, current, i, and internal resistance, r, is    ℰ = v + irin this case, the emf can be interpreted as a voltage—a difference in electric potential.i would not say that it would be considered an energy. if emf can be defined as the energy/work per a unit charge from a battery or other electric source, then it is not strictly energy.