Two movers are pushing a large crate with a force of 60.0 n each one pushes north the other pushes east what is the equilibrant force

The movers are each exerting 60 N of force on the box. Their respective directions of motion are perpendicular to one another. The Pythagorean theorem can be applied to compute the resultant force. (60 N)^2 + (60 N)^2 = (Resultant Force)^2 7200 N^2 = (Resultant Force)^2 By taking the square root of each side of the above equation we are able to compute the resultant force: Resultant Force = 84.853 N Thus, if each of the movers exerts 60 N on the crate, and the direction of forces are two the north and the to the east, the resultant force will measure 84.853 N.

The answer is a.  i hope this

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j