Physics, 31.07.2019 00:00 montoyaricardo3550

Matt forgot to put the fabric softener in the wash. as his socks tumbled in the dryer, they became charged. if a small piece of lint with a charge of +1.25 e -19 c is attracted to the socks by a force of 3.0 e -9 n, what is the magnitude of the electric field at this location?

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I can't remember how to solve this kind of problem.
So, in desperation, I take a hard look at the units.

I do remember that electric field is measured in volts per meter,
and 1 volt/meter means 1 newton/coulomb. And there it is !
The problem has a quantity of [newtons] and a quantity of [coulombs]
in it. If I divide those, the quotient will be [newton/coulomb], and THAT's
electric field strength !

(3.0 x 10⁻⁹ N) / (1.25 x 10⁻¹⁹ C)

= 2.4 x 10¹⁰ N / C

= 2.4 x 10¹⁰ volts/meter .

Answer from: jetblackcap

$E = 2.4 \times 10^{10} N/C$

Explanation:

As we know that electric field is defined as the force experienced by a unit charge placed in external electric field.

now we know that

$q = 1.25 \times 10^{-19} C$

$F = 3.0 \times 10^{-9} N$

now we know that force is related to electric field intensity as per the following relation

F = qE

$3 \times 10^{-9} = 1.25 \times 10^{-19} E$

$E = \frac{3 \times 10^{-9}}{1.25 \times 10^{-19}}$

$E = 2.4 \times 10^{10} N/C$

Answer from: Quest

measure their densities same density, same sub

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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