Anasa spacecraft measures the rate r of at which atmospheric pressure on mars decreases with altitude. the result at a certain altitude is: =r0.0421·kpakm−1 convert r to ·jcm−4 .

this is simple question of conversion of unit But as we can see here that one is in kpa or kilo pascal which is a unit of pressure while another is in joule which is unit of energy but if we do the dimension matching we could see that 1pa = 1J/m^3 and 0.0421kpa/km=0.0421pa/m now putting above equation as substitution 0.0421pa/m=0.0421J/m^4 100 cm = 1 m putting it we get R= 4.21Ă—10^-10 J/cm^4

Ibelieve the answer is b

Attach the free body diagram and i will you answer the question.! : d