Physics, 31.07.2019 07:00 autumnskye1

Calculate the orbital period for jupiter's moon io, which orbits 4.22×105km from the planet's center (m=1.9×1027kg) .

Answers: 1

Show answers

Answers

150000 seconds or approximately 1.7 days. The equation for the orbital period is: Ď„=âš((4Ď€^2/ÎĽ)a^3) where Ď„ = Period ÎĽ = standard gravitational parameter (GM) a = semi-major axis It's generally better to use ÎĽ rather than the product of G and M since we know ÎĽ more accurately than either G or M in many cases from observations of satellites around the various planets. For instance in the case of Jupiter, we know ÎĽ is 1.26686534(9)Ă—10^17 whereas we only know it's mass at 1.8982x10^27 kg and G at 6.674x10^-11 m^3/(kg*s^2). Anyway, let's first calculate ÎĽ based upon the data given: ÎĽ = 1.9x10^27 kg * 6.67ex10^-11 m^3/(kg*s^2) ÎĽ = 1.26806x10^17 m^3/s^2 Now let's substitute the known values into the equation for the orbital period. Ď„=âš((4Ď€^2/ÎĽ)a^3) Ď„=âš((4Ď€^2/1.26806x10^17)(4.22x10^8)^3) Ď„=âš((4*9.869604401/1.26806x10^17)(7.5151448x10^25) Ď„=âš((39.4784176/1.26806x10^17)(7.5151448x10^25) Ď„=âš((3.11329256x10^-16)(7.5151448x10^25) Ď„=âš(2.3396844x10^10) Ď„=152960.2706 Rounding to 2 significant figures since that's the precision of the least accurate datum, we get 150000 seconds, or approximately 1.7 days.

Answer from: Quest

terd muffin is the correct answer

Answer from: Quest

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

$p(t)=0.3t^2+6t+80$

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

$p(0)=0+0+80=80$

according to question, we have said that if the population has twice its initial population, then it becomes

$p(t)=2\times 80=160$

so, time taken to reach this above mentioned population is given by

$160=0.3t^2+6t+80\\\\160-80=0.3t^2+6t\\\\80=0.3t^2+6t\\\\0.3t^2+6t-80=0\\\\\text{using quadratic formula ,we get }\\\\t_{1,\: 2}=\frac{-60\pm \sqrt{60^2-4\cdot \: 3\cdot \: 800}}{2\cdot \: 3}\\\\t=-29.14\ and\ t=9.149$

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

Another question on Physics

Physics, 22.06.2019 06:00

What are atoms of the same element with varying number of neutrons

Answers: 3

Answer

Physics, 22.06.2019 14:10

In one or two sentences, describe how you did in the balancing game. in a few more sentences, explain one strategy you learned for balancing more complex equations.

Answers: 2

Answer

Physics, 22.06.2019 17:00

Amajor difference radio waves, visible light, and gamma rays is the of the photons, which results in different photon frequencies and wavelengths

Answers: 1

Answer

Physics, 22.06.2019 17:00

Since the energy was not raising the temperature of the water during these segments, what was the energy used to do instead? your answer must include an explanation of what is happening to the molecules.

Answers: 3

Answer

You know the right answer?

Calculate the orbital period for jupiter's moon io, which orbits 4.22×105km from the planet's center...

Questions