A95-kilogram student climbs 4.0 meters up a rope in 3.0 seconds. what is the power output of the student

Given: Mass m = 95 Kg;      Height h = 4.0 m;    Time t= 3.0 s

Required: Power output

Formula: P = W/t.    but Work = Force x distance    Force = mg  

               Distance is equal to Height h

P = mgh/t

P = (95 Kg)(9.8 m/s²)(4.0 m)/3.0 s

P = 1,242.33 J/s 

P = 1.66 Horsepower

    5.5 n======    assuming that      we have      m = 0.145 kg    a = 38 m/s²therefore    5.51 n, but two significant figures.final answer: 5.5 n