A25kg ball is thrown into the air. when thrown it is going 10 m/s. calculate how high it travels?

According to law of conservation of energy;
potential energy at the top = kinetic energy at the bottom
as the ball travels upwards, its kinetic energy is converted into potential energy, such that at its maximum height, all kinetic energy will be converted into potential energy.
potential energy (pe) = mass(m)×gravitational acceleration(a)×height(h)
where m= 25 kg, a= 9.8 m/s² and h =?
kinetic energy(ke)= 0.5×mass(m)×velocity(v)²
where m=25 kg, and v=10, v=100
ke=0.5×25×100=1250 j
pe = 1250j=25×9.8×h
height = 1250/(25×9.8) = 5.10 m

No because scientist are still changing there mines today so they are not correct to this day