The voltage drop across the resistor is the product of the (constant) resistance r of the resistor, and the current i(t) passing through the resistor. the voltage drop across a capacitor is equal to q c , where q(t) is the charge on the capacitor, and the constant c is the capacitance of the capacitor. across a voltage source (typically a battery or a power supply), the voltage increases by v(t) , so the voltage drop is is −v(t) . the current passing through the resistor and the charge on the capacitor are related by the equation i = dq/dt . write a differential equation for the charge q(t) on the capacitor as a function of time. your answer should depend on q, v , and the constants r and c , but not on i . in your answer, write just q and v for the functions q(t) and v(t) . remember to insert a space or explicitly type "*" between two letters to indicate multiplication.