What is the electric flux through one side of a cube that has a single point charge of -3.00 µc placed at its center?

From Gauss's Law, we can calculate the electric flux through all the surfaces of the cube, then divide by 6.

Using Symmetry, we can get rid of the intergal for Gauss's Law.

E * A = Qencl / 

where  = 8.85*10^-12

Well, the charge is -3.00*10^-6 C

We can divide -3.00*10^-6 C / 8.85*10^-12 F/m

This gets us a flux of 338983.0508 Nm^2

Divide by 6 and we get the flux through one side:

338983/6 = 56497.1Nm^2

I'm not to sure if it's right, but hope this helps!

Go to the bathroom and vape

There is no graph to look at on here, but i shall explain them to you. a line graph is just in its title it’s a graph with a line running through the dots to show an increase or decrease. a bar graph is used to show how much or how little something is so a comparison. a scatter plot is used to graph points to tell the data. and i don’t know what a histogram is.