Two objects a and b have the same size and shape, but a is twice as heavy as b. when they are dropped simultaneously from a tower, they reach the ground at the same time. which has a greater momentum?

By definition we have that momentum is the product of the mass of the object by the velocity of the object. In other words:
 p = m * v
 Both objects have the same speed because they reach the ground at the same time.
 However, object a is heavier than object b. The weight of the objects is:
 a = 2m
 b = m
 Therefore the momentum of a and b is
 pa = 2mv
 pb = mv
 Object a has the greatest momentum
 Answer
 pa> pb
 2mv> mv

In general momentum is defined as the product of mass and velocity. It is expressed as momentum (P) = mass ( m in Kgs) *velocity ( v in m/s) ie P = m * v kgm/s

    Given :
   Two objects of same size and shape a and b
  The velocity of the both the bodies are same ie velocity =v1 = v2=v -eqn 1 But they differ in heaviness as follows :
   The heaviness of the object a is two times of b
  ie a =2b or a/b = 2 or a : b = 2 : 1
   mass of the body m1= 2a --eqn-2
  momentum of the body is a (P1)= 2m1* v
  mass of the body m2= b --eqn 3
  momentum of the body b (P2) = m1 * v
  the momentum of the two bodies are P1 = P2
  ie m1*v1 = m2*v2
  P1 : P2 = m1*v1 : m2 * v2
  sub the value of v2,v1 from eqn 1, m1=2a, m2=b
   P1 : P2 = 2av : bv
  P1 : P2 = 2a : b
  ie (P1/P2)= (2a/b) -- eqn 4
    Ans :-
   from the above eqn 4 -it is obvious the momentum of body a is twice of body b
   ie momentum of the body a is greater.

Kinetic energy = 1/2mv^2. since the mass is constant we can form a ratio of it's kinetic energy at 60 divided by that at 30 to see ke(60)/ke(30) = +(60^2)/30^2). this may be said to 300% increase.