Apiano wire has a length of 81 cm and a mass of 2.0 g. if its fundamental frequency is to be 394 hz, its tension must be

Frequency = 394 Hz
 Length of the string L = 81 cm = 0.81 m
 Mass of the string = 0.002 kg
 Tension T = ?
 Wave length of the string is two times the length.
  n x lambda = 2L, we also have lambda = vt = v / f, t is time period and given n = 1.
  Therefore L = v / 2f => v = 2fL
 Deriving form force equation, force here is tension T so
  v = squareroot of (TL/m) hence
   2fL = squareroot of (TL/m) => 4 x f^2 x L^2 = (T x L) / m => T = 4 x f^2 x L x m
 T = 4 x 0.81 x (394)^2 x 0.002 = 4 x 0.81 x 155236 x 0.002
 T = 1005.9 N = 1.006 x 10^3 N

Answer the above statement is ( false );