Max is pushing on the edge (2.4 m from the center) of the merry-go-round to make it rotate. maya is riding on the merry-go-round, sitting 1.2 m from the center. if max increases the merry-go-round angular speed from 0.52 rev/s to 1.5 rev/s in 2.2 s, what is the merry-go-round angular acceleration

The merry-go-round angular acceleration is about 2.8 rad/s²

Centripetal Acceleration can be formulated as follows:

a = Centripetal Acceleration ( m/s² )

v = Tangential Speed of Particle ( m/s )

R = Radius of Circular Motion ( m )

Centripetal Force can be formulated as follows:

F = Centripetal Force ( m/s² )

m = mass of Particle ( kg )

v = Tangential Speed of Particle ( m/s )

R = Radius of Circular Motion ( m )

Let us now tackle the problem !

Given:

initial angular speed = ωo = 0.52 rev/s = 1.04π rad/s

final angular speed = ω = 1.5 rev/s = 3π rad/s

time taken = t = 2.2 s

Asked:

angular acceleration = α = ?

Solution:

We will use formula for angular acceleration to solve this problem:

Grade: High School

Subject: Physics

Chapter: Circular Motion

c. rb

explanation:

the atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons.