How far can a mother push a 20.0 kg baby carriage, using a force of 62 n, if she can only do 2920 j of work? question 3 options: a. 1240 m b. 47.09 m c.146 m d. 3.1 m question 4 (20 points) question 4 unsaved a force used to lift a 25 kg mass to a height of 12 m in 5 sec does 2100 j of work. how much force is used? question 4 options: a. 84 n b. 175 n c. 300 n d. 2.08 n question 5 (20 points) question 5 unsaved a force used to lift a 25 kg mass to a height of 24 m in 5 sec does 2120 j of work. calculate the power. question 5 options: a. 600 w b. 424 w c. 84.8 w

1) The correct answer is B. 47.09 m

In fact, the work done by the mother is

where F is the force she applied and d is the distance covered by the baby carriage. We are told that the maximum work she can done is , while the force she applies is F=632 N, therefore by rearranging the previous equation we find the distance travelled by the baby carriage:

2) The correct answer is B. 175 N.

As before, the work done is

where F is the force applied and d is the height at which the mass has been lifted. In this case, W=2100 J and d=12 m, therefore the force used is

3) The correct answer is B. 424 W.

The power is the ratio between the work done and the time taken, so we have:

the total distance traveled by the car is

30km + 49km = 79 km .

f is prop to m1xm2 double m1 double force