How much work is done by the force lifting a
0.1-kilogram hamburger vertically upward at
constant velocity 0.3 meter from a table?
(1) 0.03 j (3) 0.3 j
(2) 0.1 j (4) 0.4 j

The work done in lifting the hamburger is equal to the increase in gravitational potential energy of the hamburger, given by

where

m=0.1 kg is the mass of the hamburger

is the gravitational acceleration

is the increase in height of the hamburger

Substituting numbers into the equation, we find

So, the correct answer is

(3) 0.3 J

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts