The total momentum of two marbles before collision is 0.06 kg-m/s. no outside forces act on the marbles. what is the total momentum of the marbles after the collision

If you want individual total momentum,
it depends

- on the masses of the marbles
- on the velocities before impact
- on the velocities after impact
- was it elastic pre/post impact (bounced off)?
- was it inelastic pre/post impact (stuck a)?

with the given info, we must assume masses and velocities of the two marbles are the same which means there are 4 possible answers. If the question is suggesting that their INDIVIDUAL momentums were 0.12 kg*m/s vs. their COMBINED momentum (0.06 kg*m/s) before impact.

1. combined momentum & inelastic

0.06 kg*m/s = (m+m)*v
0.03 kg*m/s = m×v

2. individual momentum & inelastic

0.12 kg*m/s = (m+m)*v
0.06 kg*m/s = m×v

3. combined momentum & elastic

0.06 kg*m/s = m×v1f + m×v2f (b/c vf is different)
0.06 kg*m/s = m×(v1f + v2f)

4. individual momentum & elastic

0.12 kg*m/s = m×v1f + m×v2f (b/c vf is same)
0.06 kg*m/s = m×v



IF you want COMBINED total momentum, apply law of conservation of momentum which states that momentum is conserved without external forces... so it would be the same.

0.06 kg×m/s

stands for electromotive force and it is measured in volts. despite its name, it is not actually the force in the sense of being a "pushing" or "pulling" (not measured in newtons).an equation that relates emf,  ℰ,  to a battery's terminal voltage, v, current, i, and internal resistance, r, is    ℰ = v + irin this case, the emf can be interpreted as a voltage—a difference in electric potential.i would not say that it would be considered an energy. if emf can be defined as the energy/work per a unit charge from a battery or other electric source, then it is not strictly energy.

I'd go for the one that says that knees are fulcrums, lower legs are levers and the ankles hold loads.hope it ,happy homework/ study/ exam!