Aball has a mass of 0.25 kg and is moving to the right at 1.0 m/s. it hits a ball of mass 0.15 kg that is initially at rest. after the collision, the 0.15 kg ball moves off to the right with a velocity of 0.75 m/s. what is the final velocity of the 0.25 kg ball?

Hello!!

So we have a conservation of momentum problem here.

we are told we have .25kg ball with velocity of 1.0m/s. It collided with .15kg ball with initial velocity of zero and ending velocity is .75m/s

p=mv is momentum. So in this case we find each balls momentum and find the difference then set that momentum value equal to the first ball * v1f and solve for the final velocity of the first ball(v1f). So we have

p1=.25kg*1.0m/s = .25(kg*m/s) so now we find second ball momentum.

p2=.15kg*.75m/s= .113kg*m/s

so now we find the change in momentum is .25-.113=.137

So we have

.137kg*m/s=.25kg*v1f so final velocity of first ball is

v1f=.137/.25= 0.55m/s in the positive x direction.

Hope this helps you understand the concept Thank you so much!!

0.55 m/s to the right is the answer.

English can you write this in english do we can you

The answer is b.the gaseous state is electrically positive, while the plasma state is electrically negative.