Aspring with a spring constant k of 44 n/m is stretched a distance of 14 cm (0.14 m) from its original unstretched position. what is the increase in potential energy of the spring? j

The elastic potential energy of a spring is given by

where k is the spring's constant and x is the displacement with respect to its unstretched position. 

The initial potential energy of the spring is zero, because it is in unstretched postion, therefore x=0. The final potential energy is instead, using  and ,


And so, the increase in potential energy is