"(a) how much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 6.00 cm2? (assume air has a dielectric strength of 3.00 ✕ 106 v/m and dielectric constant of 1.00.)"

The voltage value for the electric breakdown is given by
(1)
where  is the dielectric strenght of the air while d is the distance between the two plates of the capacitor.

For a parallel plate capacitor, the capacitance is given by
(2)
where Q is the charge on the capacitor, V the voltage applied,  is the dielectric constant in air and  is the area of the plates in our problem. 

If we use the breakdown voltage given by equation (1) and replace V in equation (2) with this value, we find:

and from this, we can find the maximum charge allowed on the capacitor before the break down:

Global warming was a major concern some people do not care global warming is fake it is not real the percentage of it happening  is slight 

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j